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An electron moves a distance of 8cm when accelerated from rest by an electric field of strength 3 xx 10^(4) NC^(-1). Calculate the tme of travel. |
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Answer» Solution :Data supplied, `S=8 xx 10^(-2), u=0, E=3 xx 10^(4) NC^(-1), q=e =1.6 xx 10^(-19)C` `m=9 xx 10^(-31)kg` `S=ut+1/2 at^(2)` `F=qE =ma therefore a=(q E)/(m)` `a=(1.6 xx 10^(-19) xx 3 xx 10^(8))/(9 xx 10^(-31))=0.533 xx 10^(16) m//s^(2) therefore S=1/2 at^(2) therefore t=sqrt((2S)/(a)` `t=sqrt((2 xx 8 xx 10^(-2))/(0.533 xx 10^(16)))=5.48 xx 10^(-9)sec` |
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