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An electron moves in a circular orbit with a uniform speed v. It produces a magnetic field B at the centre of the circle. Prove that the radius of the circle is proportional to sqrt(V/B). |
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Answer» SOLUTION :The MAGNETIC field PRODUCE by moving electron in CIRCULAR path. `B=(mu_0i)/(2r) "" i=q/r `, q=e `=(mu_0q)/(2rt) "" t=(2pir)/v` `B=(mu_0qv)/(4pir^2) rArr r=SQRT((mu_0qv)/(4piB)) rArr r prop sqrt(v/B)` |
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