1.

An electron moves perpendicular to uniform magnetic field B, on a circle of radius r. Now, if magnetic field is made half of its initial value, what would be new radius of circular path ?

Answer»

`r/2`
`r/4`
2r
4r

Solution :For uniform circular MOTION,
`(mv^(2))/r=Bqv`
`thereforer=(mv)/(Bq)`
`thereforerprop1/B""[becausem,V,q" are same"]`
`thereforer_(2)/r_(1)=B_(1)/B_(2)=B/(B/2)`
`thereforer_(2)/r=2`
`thereforer_(2)=2r`


Discussion

No Comment Found

Related InterviewSolutions