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An electron moves through a uniform magnetic fields given by vecB=B_(x)hati+(3.0B_(x))hatj. At aparticular instant, the electron has velocity vecv=(2.0hati++4.0hatj)m//s and the magnetic force acting on it is (6.4xx10^(-19)N)hatk. The value of B_(x) (in T) will |
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Answer» `-3.0` |
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