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An electron moving perpendicular to a uniform magnetic field 0.500 T undergoes circular motion of radius 2.80 mm. What is the speed of electron ? |
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Answer» SOLUTION :CHARGE of an electron q = -1.60 `xx 10^(-19) C rArr |a| = 1.60 xx 10^(-19)` C Magnitude of magnetic field B = 0.500 T Mass of the electron, m = 9.11 `xx 10^(-31)` kg Radius of the orbit , r = 2.50 mm = `2.50 xx 10^(-3)` m Velocity of the electron, v = (q) `(RB)/(m) rArr v = 1.60 xx 10^(-19) xx (2.50 xx 10^(-3) xx 0.500)/(9.11 xx 10^(-11)) ` v = 2.195`xx 10^(8) ms^(-1)` |
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