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An electron of energy 150eV has wavelength of 10^-10m. The wavelength of a 0.60 keV electron is_ |
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Answer» We know that wavelength of an electron is given by the relation, λ = h/√2mV where, h = planks constant m = mass of electron V = energy of the electron, keeping h and m constant, we have, λ ∝ 1/√V => λ₂/λ₁ = √(V₁/V₂) => λ₂ = 10⁻¹⁰ x √(150/600) => λ₂ = 10⁻¹⁰ x 1/2 = 0.5 x 10⁻¹⁰ m Hence the wavelength of 0.60 keV electron will be 0.5 x 10⁻¹⁰ m |
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