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An electron of mass `9.1xx10^(-31)` kg is at a distance of `10 A^(@)` from a. porton of mass `1.67xx10^(-27)` kg. calculate the gravitational force of attraction between them. |
Answer» Here, `m_(1)=9.1xx10_(-31) kg, d=10A^(@)=10^(-9)m` `M_(2)=1.67xx10^(27)kg, F=?` `F=(Gm_(1)m_(2))/d^(2)=(6.67xx10_(-11)xx9.1xx10^(-31)xx1.67xx10^(-27))/(10^(-9))^(2)=1.01xx10^(-49)N` |
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