InterviewSolution
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InterviewSolution
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An electron of mass `m` and a photon have same energy `E`. The ratio of de - Broglie wavelengths associated with them is :A. `(1)/( C) ((E )/( 2 m))^(1//2)`B. `((E )/(2 m))^(1//2)`C. `C ( 2m E)^(1//2)`D. `(1)/(xC) ((2 m)/( E))^(1//2)` |
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Answer» Correct Answer - A For electron `lambda_(e) = (h)/(sqrt(2 mE))` For photon `E = pc rArr lambda_(ph) = (hc)/( E )` `rArr (lambda_(e ))/(lambda_(ph)) = (h)/(sqrt( 2m E)) xx (E )/(hc) = ((E )/(2 m))^(1//2) (1)/( c )` |
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