1.

An electron of mass m and charge e is accelerated by a potential difference V. It then enters a uniform magnetic field B applied perpendicular to its path. The radius of the circular path of the electron is

Answer»

`r=((2mV)/(EB^(2)))^(1//2)`
`r=((2meV)/(B^(2)))^(1//2)`
`r=((2mB)/(EV^(2)))^(1//2)`
`r=((2B^(2)V)/(em))^(1//2)`

ANSWER :A


Discussion

No Comment Found

Related InterviewSolutions