1.

An electron of mass m and charge e is accelerated from rest through a potential difference V in vacuum. Its final velocity will be

Answer»

`sqrt((2eV)/(m))`
`sqrt((eV)/(m))`
`(eV)/(2m)`
`(eV)/(m)`

Solution :K.E. gained by an electron when accelerated through a potential DIFFERENCE V, `(1)/(2) MV^(2) = eV or v = sqrt((2eV)/(m))`


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