1.

An electron of mass m_(e) and a proton of mass m_(p) are moving with thesame speed. The ratio of their deBroylie's wavelength lamda_(e)//lamda_(p) is :

Answer»

1
1836
`(1)/(1836)`
918

Solution :de-Broglie.s WAVELENGTH,
`lambda=(h)/(mv)`
For electron,
`lambda_(E)=(h)/(m_(e)v)`
for photon
`lambda_(p)=(h)/(m_(p)v)`
`:.(lambda_(e))/(lambda_(p))=(h//m_(e)v)/(h//n_(p)v)`
`(lambda_(e))/(lambdal_(p))=(m_(p))/(m_(e))`
`(lambda_(e))/(lambda_(p))=(1.67xx10^(-27))/(9.1xx10^(-31))`


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