An electron of mass m_(e) and a proton of mass m_(p) are moving with thesame speed. The ratio of their deBroylie's wavelength lamda_(e)//lamda_(p) is :

An electron of mass m_(e) and a proton of mass m_(p) are moving with t

1.	An electron of mass m_(e) and a proton of mass m_(p) are moving with thesame speed. The ratio of their deBroylie's wavelength lamda_(e)//lamda_(p) is :
Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a><br/>1836<br/>`(1)/(1836)`<br/>918</p>Solution :de-Broglie.s <a href="https://interviewquestions.tuteehub.com/tag/wavelength-1450414" style="font-weight:bold;" target="_blank" title="Click to know more about WAVELENGTH">WAVELENGTH</a>, <br/> `lambda=(h)/(mv)` <br/> For electron, <br/> `lambda_(<a href="https://interviewquestions.tuteehub.com/tag/e-444102" style="font-weight:bold;" target="_blank" title="Click to know more about E">E</a>)=(h)/(m_(e)v)` <br/> for photon <br/> `lambda_(p)=(h)/(m_(p)v)` <br/> `:.(lambda_(e))/(lambda_(p))=(h//m_(e)v)/(h//n_(p)v)` <br/> `(lambda_(e))/(lambdal_(p))=(m_(p))/(m_(e))` <br/> `(lambda_(e))/(lambda_(p))=(1.67xx10^(-<a href="https://interviewquestions.tuteehub.com/tag/27-298706" style="font-weight:bold;" target="_blank" title="Click to know more about 27">27</a>))/(9.1xx10^(-31))`</body></html>

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An electron of mass m_(e) and a proton of mass m_(p) are moving with thesame speed. The ratio of their deBroylie's wavelength lamda_(e)//lamda_(p) is :

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