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An electron of mass m is kept in a vertical electric field of magnitude E. What must be the value of E so that the electron doesn’t fall due to gravity?(a) m*g*e(b) \(\frac {e}{(m*g)}\)(c) \(\frac {(m*g)}{e}\)(d) \(\frac {1}{(m*g*e)}\)This question was addressed to me in quiz.The above asked question is from Electric Field in chapter Charges and Fields of Physics – Class 12 |
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Answer» The CORRECT OPTION is (c) \(\frac {(m*g)}{e}\) |
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