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An electron revolving in an orbit of radius `0.5 Å` in a hydrogen atom executes per secon. The magnetic momentum of electron due to its orbital motion will beA. `1.256 xx 10^(-23) A m^(2)`B. `653 xx 10^(-26) A m^(2)`C. `10^(-3) A m^(2)`D. `256 xx 10^(-26) A m^(2)` |
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Answer» Correct Answer - A `M = 1 A = e f pi r^(2)` `= 1.6 xx 10^(-19) xx 10^(16) xx 3.14 xx (0.5 xx 10^(-10)) ^(2) A m^(2)` `= 1.256 xx 10^(-23) A m^(2)` |
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