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An electron starts from rest and travels `0.9`m in an electric field of `200`V//m. After this , it enters a magnetic field at right angle to its direction of motion . If the radius of circular path of the electron is `9`cm, the magnetic field induction is (Given e=`1.6xx10^(-19)`C,` m=9xx10^(-31)`g) `A. `5xx10^9-4wb//m^(2)`B. `5xx10^(-5)wb//m^(2)`C. `5xx10^(-3)wb//m^(2)`D. `5xx10^(-2)wb//m^(2)` |
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Answer» Correct Answer - A `v^(2)-U^(2)=2as,V^(2)=2(Eq)/mSRightarrowV=sqrt(2(Eq)/mS)r=(mV)/(Bq)RightarrowB=(mV)/(rq)` |
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