1.

An electrons is moving round the nucleus of a hydrogen atoms in a circularorbit of radius r. The coulomg forceoversetto Fbetween the two is(where K =( 1)/( 4pi in _0))

Answer»

` K(E^(2))/(r^(3)) oversetto r `
` k(e^(2))/( r^(2)) oversetto r `
` -k(e^(2))/( r^(3)) oversetto r `
` -k(e^(2))/( r^(2)) oversetto r `

Solution :Force F=`( kq_1kq_2)/(r^(3)) oversettor =(KE^(2))/(r^(3)) oversetto r.`Here-ve sign shows that force between hydrogen nucleus i.e. PROTON and the electron is attractive in nature.


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