1.

An electrons is revolving in n=3 orbit. What will be the magnetic field at the centre of hydrogen atom.

Answer»

a) 0.1 T
b) 5T
c) 0.5T
d) 0.05T

Solution :`B=(mu_(0)i)/(2R)`
`=(mu_(0))/(2r)XX(eV)/(2pir)=(mu_(0)eV)/(4pir^(2))`
`V=2.18xx10^(6)xx(1)/(3)=0.73xx10^(6)=7.3xx10^(5)m//s`
`r=0.529`Å`xx(3^(2))/(1)=7.461`Å
`B=(10^(7)xx1.6xx10^(-19)xx7.3xx10^(5))/(4.761xx4.761xx10^(-20))=0.515T`


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