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An electtron and a photon have same wavelength . If `p` is the moment of electron and `E` the energy of photons, the magnitude of `p//E in S I` unit isA. `3.0 xx 10^(8)`B. `3.33 xx 10^(-9)`C. `9.1 xx 10^(-31)`D. `6.64 xx 10^(-34)` |
Answer» Correct Answer - B `lambda = (h)/(p)` (for electron) or `p = n//h` and `E = (hc)/(lambda)` (for photon) `:. (p)/(E) = (1)/( c) = (1)/(3 xx 10^(8)) = 3.33 xx 10^(-9) s m^(-1)` |
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