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An element Delta I = Delta x overset(^)(i)is placed at the origin and carries a large current I = 10A. What is the magnetic field on the y-axis at a distance of 0.5 m. Deltax = 1 cm. |
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Answer» Solution :From Biot-Savart's Law, `|bar(d BETA)| = 1 dl sin theta//R^2` `dI = Delta X = 1 CM = 10^(-2) m, I = 10 A, r= y = 0.5 m` `mu_(0)/ 4pi = 10^(-7) Tm//A, theta = 90^@` so sin `theta=1` `|bar(d B)| = (10^(-7) xx 10xx10^(-2))/(25 xx 10^(-2)) = 4 xx 10^(-8)` T along + z axis |
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