. An element has a body-centred cubic (bcc) structure with a cell edge – InterviewSolution

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1.	. An element has a body-centred cubic (bcc) structure with a cell edge of288 pm. The density of the element is 7.2 g/cm3. How many atoms arepresent in 208 g of the element?
Answer» Formula units per unit cell Z = 2 for BCC cubic unit cell lattice parameter a = 28 pm=288x10-8cmVolume V = a3=2.39X10-23cm3Density d = 7.2g/cm3NA = Avogadro constant = 6.022x10²³Molecular mass M =?We know that Density d = ZM/NA Xa3,M = dxNA x a3/ZOn Substituting valuesM= 7.2g/cm3x(6.022x10²³)X (6.022x10²³)/2= 51.8gmol-151.8 g of element contains 6.022X1023208g of this element contains=?= 6.022X1023X208/51.8=2.42X1024atoms.

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