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An element hobbyist is building a radio which reequires 150 Omega in her circuit, but she has only 220Omega, 79 Omega and 92 Omega resistors available. How can she connect the available resistor to get desired value of resistance? |
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Answer» Solution :REQUIRED effectiveresistance `=150Omega` Given resistors of RESISTANCE, `R_(1)=220Omega, R_(2)=79Omega, R_(3)=92Omega` Parallel combination of `R_(1) and R_(2)` `(1)/(R_(p))=(1)/(R_(1))+(1)/(R_(2))=(1)/(220)+(1)/(79)=(79+220)/(220xx79)` `R_(p)=58Omega`  Parallel combination of `R_(p) and R_(3)` `R_(s)=R_(p)+R_(3)=58+92` `R_(s)=150Omega` Parallel combination of `220Omega and 79Omega` in series with `92Omega` |
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