1.

An element with Z = 11 emits Kalpha-X-ray with wavelength lamda. The atomic no. of element which emits Kalpha X-ray of wavelength 4lamda is:

Answer»

6
4
11
44

Solution :`sqrt(V)=a(z-b)`
`v=a^(2)(z-b)^(2)`
`:. (C)/(LAMBDA)=a^(2)(z-b)^(2)`
`:.(lambda_(1))/(lambda_(2))=((z_(2)-1)^(2))/((z_(1)-z)^(2))` here b=1
put `z_(1)=11, lambda_(1)= lambda, lambda_(2)= 4lambda_(2)` & find `z_(2)`
Then `z_(2)=6.`


Discussion

No Comment Found

Related InterviewSolutions