An element X on treatment with oxygen gives Y which on hydrolysis produces Z.Z on treatment with higher oxide of carbon 'A' gives milky white precipitate 'B'. Identify X, Y, Z, A and B?

An element X on treatment with oxygen gives Y which on hydrolysis prod

1.	An element X on treatment with oxygen gives Y which on hydrolysis produces Z.Z on treatment with higher oxide of carbon 'A' gives milky white precipitate 'B'. Identify X, Y, Z, A and B?
Answer» Solution :As Z on treatment with oxide "A" of carbon GIVES MILKY appearance to the solution by forming. B, Z is `Ca(OH)_(2), A "is" CO_(2), B "is" CaCO_(3)`. As Z is produved by hydrolysis of Y. Y is CAO. As Y is prepared by treating "X" with oxygen, X is Ca. `underset(("X"))(Ca + O_(2)) rarr underset(("Y"))(CaO)` `underset("Y")(CaO) + H_(2)O rarr underset("Z")(Ca(OH)_(2))` `underset("Z")(Ca(OH)_(2)) + underset("A")(CO_(2)) rarr underset("B")(CaCO_(3)) + H_(2)O`