An elevator begins from 20 m above the ground. It descends into a mine

1.	An elevator begins from 20 m above the ground. It descends into a mine shaft at the rate of 6 m per minute. What will beits position after 15 minutes ?
Answer» Since the elevator is going down, so the distance covered by it will be represented by a negative integer. Change in position of the elevator in one minute = – 6 m. Change in position of the elevator in 15 minutes = 15 × (-6) = – 90 m. So, the final position of the elevator – 20 + (-90) = – 70 m. The elevator is at 70 m below the ground level.

An elevator begins from 20 m above the ground. It descends into a mine shaft at the rate of 6 m per minute. What will beits position after 15 minutes ?

Answer»

Since the elevator is going down, so the distance covered by it will be represented by a negative integer.

Change in position of the elevator in one minute = – 6 m.

Change in position of the elevator in 15 minutes = 15 × (-6) = – 90 m.

So, the final position of the elevator – 20 + (-90) = – 70 m.

The elevator is at 70 m below the ground level.