an elevator descends into a mine shaft at the rate of 5m/min. what wil

1.	an elevator descends into a mine shaft at the rate of 5m/min. what will be its position after one hour? if it begins to descend from 35m above the ground, what will be its position after 30 minutes?
Answer» Answer: Step-by-step explanation: An elevator descends into mine shaft at the rate of 5 meter PER minute. so for 1 min elevator descends 5metres. the position of the elevator after ONE hour = we know 1 hour =60 min so 60MIN x 5metres=300 meters.. but the elevator began to descend from 15 meters above so, 300-15="285metres." and its position after 45 mins is 45metres x 5 mins=225 meters. and the elevator has descended from 15 meters above so 225-15 meters="210metres."

an elevator descends into a mine shaft at the rate of 5m/min. what will be its position after one hour? if it begins to descend from 35m above the ground, what will be its position after 30 minutes?

Answer»

Answer:

Step-by-step explanation:

An elevator descends into mine shaft at the rate of 5 meter PER minute.

so for 1 min elevator descends 5metres.

the position of the elevator after ONE hour =

we know 1 hour =60 min so 60MIN x 5metres=300 meters..

but the elevator began to descend from 15 meters above so,

300-15="285metres."

and its position after 45 mins is 45metres x 5 mins=225 meters.

and the elevator has descended from 15 meters above so

225-15 meters="210metres."