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An elevator descends into a mine shaft at the rate of 6m /mins if the descent starts from 10m above the ground level how long will take to reach-350m |
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Answer» Step-by-step explanation: Considering the elevator to be at constant speed and the destination to be 350 m below ground level, The elevator has to TRAVEL 10m till the ground, then 350 m more. So, the total distance to travel is 360 m If the elevator's speed is 6 metres/minute, Then, Time= Distance/Speed = 360/6 =1 hour ∴Thus the elevator would take 1 hour to reach its destination. |
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