1.

An elevator descends into a mine shaft at the rate of 6 m/min. If the descentstarts from 10 m above the ground level,how long will it take to reach - 350m​

Answer» TOTAL d=350+10=360mspeed or rate of ELEVATOR is 6m/60s=0.1m/stotal t = d/speed=360/0.1=3600 SEC =60 MIN


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