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an elevator descends into a mine shaft at the rate of 5m./min. if the descend start from 20m above the ground the how long will it take to reach 2/50m |
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Answer» Answer: 50m/2 = 25m Speed = 5m/min Step-by-step explanation: If the ELEVATOR starts the descend from 20m above the ground, then - TOTAL DISTANCE to be covered by the elevator = 25m+20m = 45m Time TAKEN = 45m/5 = 9 minutes |
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