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An elevator in which a man is standing is moving upwards with a speed of 10m/sec . If the man drops a coin from a height of 2.45 metre, after what time it reaches the floor of the elevator. |
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Answer» SOLUTION :Hereu=0 beacause lift is moving. RELATIVE velociy of COIN w.r.t lift is zero, a `a = + G = 9.8 m/s^2 t = ? s = 2.45 m` `As S = ut+1/2xx9.8t^2=4.9t^2` `t^2 = 2.45/4.9 = 1/2 or t = 1/(sqrt2sec)` |
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