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An elevator of mass M is accelerated upwards by applying a force F.A mass m initially situated at a height of 1 m above the floor the elevator is falling freely. It will hit the floor of the elevator after a time equal toA. `sqrt((2M)/(F+mg))`B. `sqrt((2M)/(F-mg))`C. `sqrt((2M)/(F))`D. `sqrt((2M)/(F+Mg))` |
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Answer» Correct Answer - C `a_(e)=(F)/(m)uarr` `a_(s)=-gdarr` `a_(s//e)=a_(s)-a_(e)=(F)/(m)+g=(F+Mg)/(M)` `s=ut+(I)/(2)at^(2)` `1=(1)/(2)((F+Mg)/(M))t^(2)` `t=sqrt(2(M)/(F+Mg))` |
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