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An elevator which can carry a maximum load of `1800kg` is moving with a constant speed of `2ms^(-1)`. The frictional force opposing the motino is `5000N`. Calculate the minimum power delivered by the motor to the elevator in watt and hp ? Take `g=10m//s^(2)` |
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Answer» Here, `m=1800kg, upsilon=2ms^(-1),` `f=5000N,P=?` Minimum force required to be applied, `F=mg+f=1800xx10+5000=23000N` `P=Fxxupsilon=23000xx2=46000W=46kW` `=(46000)/(746)hp=61.66hp` |
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