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An ellipse is drawn by taking a diameter of the circle `(x)^2+""y^2=""1`as its semiminor axis and adiameter of the circle `x^2+""(y""""2)^2=""4`as its semi-major axis. If thecentre of the ellipse is the origin and its axes are the coordinate axes,then the equation of the ellipse is(1) `4x^2+""y^2=""4`(2) `x^2+""4y^2=""8`(3) `4x^2+""y^2=""8`(4) `x^2+""4y^2=""16` |
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Answer» `(x-1)^2 + y^2 = 1` `r=1` `d=2` `b=2` and `x^2 + (y-2)^2 = 4` `r=2` `d= 4` `a=4` eqn of ellipse `x^2/a^2 + y^2/b^2 = 1` `x^2/16 + y^2/4 = 1` `(x^2 + 4y^2)/16=1` `x^2 + 4y^2 = 16` option 3 is correct |
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