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An emf of 20 V is applied at time t = 0 to a circuit containing in series 10 mH inductor and 5Omega resistor. The ratio of the currents at time t = oo and t = 40 s is close to (take e^2 = 7.389) |
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Answer» 1.06  `=4(1-e^(-500t))` `rArr` At `t=oo [("INFINITE"),(because e=e)]` i=4(1-e) `i_0=4A`  `i_0=4A` `rArr` At t=40 s `i_(40) = 4(1-e^(-500xx40))` `=4(1-1/((e^2)^10000))` `=4(1-1/((7.29)^10000))` `i_0/i_40 = 1/(1(1/((7.29)^10000)))` =1.06 |
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