An energetic a-particle experiences head-on collision with nucleus having Z = 85. If distance of closest approach is 1.85xx10^(-14)m then calculate energy of a particle.

An energetic a-particle experiences head-on collision with nucleus hav

1.	An energetic a-particle experiences head-on collision with nucleus having Z = 85. If distance of closest approach is 1.85xx10^(-14)m then calculate energy of a particle.
Answer» 23.13 MEV 13.2 MeV 10 MeV 20 MeV Solution :13.2 MeV Kinetic energy of a particle = P.E. at `r_(0)` DISTANCE `=(kxxZexx2e)/(r_(0)xxe)toeV` `=(9xx10^(9)xx85kxx2xxe^(2))/(1.85xx10^(-14)xxe)` `=(9xx10^(9)xx170xx1.6xx10^(-19))/(1.85xx10^(-14))` `=1323.24xx10^(4)eV` `=13.23xx10^(6)eV` `=13.23MeV`

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An energetic a-particle experiences head-on collision with nucleus having Z = 85. If distance of closest approach is 1.85xx10^(-14)m then calculate energy of a particle.

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