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An engine exerts a force `F=(20hati-3hatj+5hatk)` N and moves with velocity `v=(6hati+20hatj-3hatk) ms^(-1)`. The power of the engine (in watt) isA. 45B. 75C. 20D. 10 |
Answer» Correct Answer - A (a) Power of the engine, `P=F.v=(20hati-3hatj+5hatk).(6hati+20hatj-3hatk)` =120-60-15=45 W |
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