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An equilateral glass prism has a refractive index 1.6 in air. Calculate the angle of minimum deviation of the prism, when kept in a medium of refractive index 4sqrt(2)//5 |
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Answer» Solution :Here, `angleA = 60^(@), n_("glass") = 1.6` and `n_("MED") = (4sqrt(2))/5` If `D_(m)` be the angle of MINIMUM deviation in given MEDIUM, then `n=(n_("glass"))/(n_("med")) = (sin(A+D_(m))/2)/(sin(A/2)) rArr 1.6/(4sqrt(2)/5) = (sin(60^(@) + D_(m))/2)/(sin(60^(@))/2)` `rArr 30^(@) = D_(m)/2 = 45^(@) rArr D_(m) = 30^(@)` |
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