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An equilateral prism is kept in air and for a particular ray angle of minimum deviation is38^@. If the prism is immersed in water theangle of minimum deviation =........ Refractive index of water is 1.33 |
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Answer» SOLUTION :`RARR(n_g)/(n_a) = (sin""((60 + 38)/(20))^(@))/(sin 30^@)` Taking `n_a = 1 , n_g = (sin 49^@)/(sin 30^@) = 1.509` When prism is immersed in water, `n_(g)/(n_w) = (sin""((60 + delta_m)/(2)))/(sin 30^@)` But `n_w = 1.33` `therefore (1.509)/(1.33)=sin((60 + delta_m)/(2))^@/0.5` `thereforesin ((60 + delta_m)/(2))^@ = (0.5 xx 1509)/(1.33) = 0.5673` `therefore (60 + delta_m)/(2) = 34^@ 36.` `thereforedelta_m = 9^@ 12.` |
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