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An error of 3% is committed in the measurement of volume of a cube. What is the percentage of error committed in the measurement of each of its sides. |
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Answer» Solution :The volume of a cube `V=L^3` l=length of each side so `long(V) = 3 log l` Differentiating both sides `DeltaV/V=3(Deltal)/l` so, `(Deltal)/l=l//3xx(DeltaV)/V=1//3xx3%=1%` |
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