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An excess of `AgNO_(3)` is added to `100mL` of a `0.01M` solution of dichlorotetraaquachromium(III) chloride The number of moles of `AgCI` precipitated would be .A. 0.001B. 0.002C. 0.003D. 0.01 |
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Answer» Correct Answer - A `AgNO_(3)+[Cr(H_(2)O)_(4)Cl_(2)]Cl toAgCl` `"Excess mole"=MV_("(lit)")` `=0.01xx(100)/(1000)` `=0.001` |
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