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An experiment takes `10` minutes to raise the temperature of water in a container from `0^(@)C "to" 100^(@)C` and another `55` minutes to convert it totally into steam by a heater supplying heat at a uniform rate. Neglecting the specific heat of the container and taking specific heat of water to be `1 "cal//g ^(@)C`, the heat of vapourization according to this experiment will come out to be:-A. `540"cal"//g`B. `530"cal"//g`C. `560"cal"//g`D. `550"cal"//g` |
Answer» Correct Answer - D Let M is mass of water and P is amount of heat supplied per unit minute. `MS_(W)(100-0) = P xx 10 …..(i)` `ML_(V) = P xx 55 …. (ii)` (i)/(ii) we get `L_(V) = 550"cal"//"g"` |
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