1.

An hydrogen atom in its ground state absorbs 10.2 eV of energy. The orbital angular momentum is increased by…….js.

Answer»

`1.05 TIMES 10^-34`
`3.16 times 10^-34`
`2.11 times 10^-34`
`4.22 times 10^-34`

Solution :`E=-13.6/n^2-(13.6/1^2)`
`10.2=13.6-13.6/n^2`
`therefore 13.6/n^2=13.6-10.2`
`therefore 13.6/n^2=3.4`
`therefore n^2=13.6/3.4`
`therefore n^2=4`
`therefore n=2`
Angular MOMENTUM
`=(nh)/(2pi)`
`=((1)times6.625 times 10^-34)/(2 times 3.14)`
`=1.0549 times 10^-34`
`approx 1.05 times 10^-34 Js`


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