An ideal choke takes a current of 10 A when connected to an ac supply of 125 V and 50 Hz. A pure resistor under the same conditions takes a current of 12.5 A. If the two are connected to an ac supply of 100 V and 40 Hz, then the current in series combination of above resistor and inductor isA. `10` ampB. `12.5` ampC. `20` ampD. `25` amp

An ideal choke takes a current of 10 A when connected to an ac supply

1.	An ideal choke takes a current of 10 A when connected to an ac supply of 125 V and 50 Hz. A pure resistor under the same conditions takes a current of 12.5 A. If the two are connected to an ac supply of 100 V and 40 Hz, then the current in series combination of above resistor and inductor isA. `10` ampB. `12.5` ampC. `20` ampD. `25` amp
Answer» Correct Answer - A `R=125/12.5 =10 Omega` `X_(L)=omegaL=2pinL=V/I=125/10=12.5` `:. 2pinL=12.5` or `2piL=12.5/50=0.25` `:. X_(L)=2piLxxn=0.25xx40=10 Omega` Impedence of the circuit `Z=sqrt(R^(2)+X_(L)^(2))=10sqrt(2)` ohm `:.` Current `=(100sqrt(2))/(10sqrt(2))=10` amp

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