InterviewSolution
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InterviewSolution
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An ideal gas at `NTP` is enclosed in an adiabatic vertical cylinder havin an area of cross section `A=27 cm^(2)` between two light movable pistons as shown in figure. Spring with force constant `K=37-- N//m` is in a relaxed state initially. Now the lower position is moved upwards a distance `h//2`, `h` being the initial length of gas column . It is observed that the upper piston moves up by a distance `h//16`. Final temperature of gas` 4//3 xx 273 K`. Take `gamma` for the gas to be `3//2`. The value of `h` isA. `1 m`B. `1.4m`C. `1.6m`D. `2m` |
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Answer» Correct Answer - C Final pressure, `P_(f)=(P_(0)+(Kh//16)/(A))` `(P_(f)V_(f))/( T_(f))=(P_(0)V_(0))/(T_(0))` `((P_(0)+(kh)/(16A))Axx((h)/(2)+(h)/(16)))/(T_(f))=(P_(0)Ah)/( T_(0))` `((10^(5)+(3700h)/( 16xx27xx10^(-4)))(9)/(16))/((4)/(3)xx273)=(10^(5))/(273)` `(1+0.856h)=(16)/(9)xx(4)/( 3)` Solving, `h=1.6 m ` |
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