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An ideal gas expands from `10^(-3) m^(3)` to `10^(-2) m^(3)` at 300 K against a constant pressure of `10^(5) Nm^(-2)`. The workdone isA. `-0.9 kJ`B. `-900 kJ`C. `270 kJ`D. `-270 kJ` |
Answer» Correct Answer - A `W=-PDeltaV` `P=10^(5)Nm^(-2)=1"atm"`, `DeltaV=10-1=9 "Litres"[1m^(3)=10^(3)L]` `W=-(1xx9xx101)/(1000)[1 L-"atom"=101 J]` `=0.9 kJ` |
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