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An ideal gas goes from State A to state B via three different process as indicate in the `P-V` diagram. If `Q_(2), Q_(3)` indicates the heat absorbed by the gas along the three processes and `DeltaU_(1), DeltaU_(2), DeltaU_(3)` indicates the change in internal energy along the three processes respectively, thenA. `Q_(1)gtQ_(2)gtQ_(3)` and `DeltaU_(1)=DeltaU_(2)=DeltaU_(3)`B. `Q_(3)gtQ_(2)gtQ_(1)` and `DeltaU_(1)=DeltaU_(2)=DeltaU_(3)`C. `Q_(1)=Q_(2)=Q_(3)` and `DeltaU_(1)=DeltaU_(2)=DeltaU_(3)`D. `Q_(3)gtQ_(2)gtQ_(1)` and `DeltaU_(1)gtDeltaU_(2)gtDeltaU_(3)` |
Answer» Correct Answer - A For all process `1,2,and 3` `DeltaU=U_(B)-U_(A)` is the same `:. DeltaU_(1)=DeltaU_(2)=DeltaU_(3)` `Now, Q = DeltaU+W` Now `W` = work done by the gas `:. Q_(1) gt Q_(2) = Q_(3)`. |
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