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An ideal gas heat engine operates in a Carnot cycle between `227^(@)C and 127^(@)C`. It absorbs `6K cal.` of heat at higher temperature. The amount of heat in `k cal` rejected to sink isA. `4.8`B. `2.4`C. `1.2D. `6.0` |
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Answer» Correct Answer - A Here, `T_(1)= 227^(@)C = 227+ 273= 500K` `T_(2)= 127^(@)C= 127+273= 400K` `Q_(1)= 6k cal Q_(2)=?` `(Q_(2))/(Q_(1))= (T_(2))/(T_(1))= (400)/(500)= 4/5` `Q_(2)= 4/5Q_(1)= 4/5xx6 kcal= 4.8Kcal` |
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