An ideal gas in thermally insulated vessel at internal `(pressure)=P_(1), (volume)=V_(1)` and absolute `temperature = T_(1)` expands irreversiby against zero external, pressure , as shown in the diagram, The final internal pressure, volume and absolute temperature of the gas are `p_(2), V_(2) and T_(2)`, respectively . For this expansion A. `q=0`B. `T_(2)=T_(1)`C. `P_(2)V_(2)=P_(1)V_(1)`D. `P_(1)V_(2)^(gamma)=P_(1)V_(1)^(gamma)`

An ideal gas in thermally insulated vessel at internal `(pressure)=P_(

1.	An ideal gas in thermally insulated vessel at internal `(pressure)=P_(1), (volume)=V_(1)` and absolute `temperature = T_(1)` expands irreversiby against zero external, pressure , as shown in the diagram, The final internal pressure, volume and absolute temperature of the gas are `p_(2), V_(2) and T_(2)`, respectively . For this expansion A. `q=0`B. `T_(2)=T_(1)`C. `P_(2)V_(2)=P_(1)V_(1)`D. `P_(1)V_(2)^(gamma)=P_(1)V_(1)^(gamma)`
Answer» Correct Answer - A::B::C Since, the vessel is thermally insulated hence q=0 Work done (W=0) is zero for free expansion `DeltaU` is also zero for free expansion, so, `T_(1)=T_(2) and P_(1)V_(1)=P_(2)V_(2)` (Isothermal process).

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