An ideal gas is initially at temperature T and volume V. Its volume is increased by `DeltaV` due to an increase in temperature `DeltaT,` pressure remaining constant. The quantity `delta=(DeltaV)/(VDeltaT)` varies with temperature asA. B. C. D.

An ideal gas is initially at temperature T and volume V. Its volume is

1.	An ideal gas is initially at temperature T and volume V. Its volume is increased by `DeltaV` due to an increase in temperature `DeltaT,` pressure remaining constant. The quantity `delta=(DeltaV)/(VDeltaT)` varies with temperature asA. B. C. D.
Answer» Correct Answer - C `(V)/(T)=(nR)/(P)=`constant `(V)/(T)=(V+DeltaV)/(T+DeltaT)` `VT+VDeltaT=VT+DeltaVT` `VDeltaT=DeltaVT` `(DeltaV)/(VDeltaT)=(1)/(T)` `delta=(1)/(T)` `delta` v/s T will be rectangular hyperbola

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An ideal gas is initially at temperature T and volume V. Its volume is increased by `DeltaV` due to an increase in temperature `DeltaT,` pressure remaining constant. The quantity `delta=(DeltaV)/(VDeltaT)` varies with temperature asA. B. C. D.

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