1.

An ideal heat engine working between 27^(@)C and 127^(@)C takes 400 cal of heat in one cycle. The work done is

Answer»

75 cal
50 cal
100 cal
200 cal

Solution :`ETA=(DW)/(DQ)`
`(1)/(4)=(dW)/(400)`
`dW=100cal(eta=1-(300)/(400)=(1)/(4))`


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