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An ideal heat engine works between source at `127^(@)C` and sink `27^(@)C`. If 800 J heat is taken from reservoir, the amount of heat rejected to sink isA. 300 JB. 400 JC. 500 JD. 600 J |
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Answer» Correct Answer - D `eta=1-(T_(2))/(T_(1))` `eta=1-(Q_(2))/(Q_(1))=1-(T_(2))/(T_(1))=(300)/(600)=(1)/(2)` `therefore (Q_(2))/(Q_(1))=(T_(2))/(T_(1))` `Q_(2)=(T_(2))/(T_(1))xxQ_(1)=(300)/(400)xx800=600J` |
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